+ 10e = 150 + 7e - Dyverse

Understanding the Context

Understanding the Equation

The given equation is:
10e = 150 + 7e
Here, e represents the base of the natural logarithm (approximately equal to 2.718), though in algebra problems like this one, e is typically used as a variable to solve for rather than a constant.

Step 1: Isolate Terms Involving e

To solve for e, begin by gathering all exponential terms on one side of the equation and the constant terms on the other. Subtract 7e from both sides:
10e – 7e = 150

This simplifies to:
3e = 150

Key Insights

Step 2: Solve for e

Now divide both sides by 3:
e = 150 / 3
e = 50

Verification

Plug e = 50 back into the original equation to check:
Left side: 10e = 10 × 50 = 500
Right side: 150 + 7e = 150 + 7 × 50 = 150 + 350 = 500

Both sides equal 500, confirming the solution is correct.

Final Thoughts

Why This Equation Matters

While exponential variables like e often appear in advanced calculus and calculus-based problems (e.g., exponential growth, decay), simpler versions like 10e = 150 + 7e help learners practice algebraic manipulation and isolate unknowns. Mastering these techniques prepares students for more complex scientific modeling and problem-solving tasks.

Tips for Solving Similar Equations

• Always move all terms involving the variable to one side.
  
• Combine constant terms on the opposite side.
  
• Divide evenly to isolate the variable.
  
• Always verify your solution by substituting back into the original equation.

Conclusion

The equation 10e = 150 + 7e simplifies neatly to yield e = 50—a straightforward example of algebraic reasoning that lays the foundation for tackling exponential equations in higher mathematics. Whether for homework, classwork, or personal practice, understanding how to solve for e enhances your analytical capabilities.