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Home » \( a_4 = 2 \times 15 + 1 = 31 \) - Dyverse

\( a_4 = 2 \times 15 + 1 = 31 \) - Dyverse

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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\text{Average} = \frac{(3v+2) + (5v-1) + (4v+7)}{3} = \frac{12v + 8}{3...
We require this average to be less than 25:
4v + \frac{8}{3} < 25
Subtract \(\frac{8}{3}\) from both sides:
4v < 25 - \frac{8}{3} = \frac{75}{3} - \frac{8}{3} = \frac{67}{3}
Now divide by 4:
v < \frac{67}{12} \approx 5.583
Since \( v \) is a positive integer, the largest possible value is \(...
4(5) + \frac{8}{3} = 20 + \frac{8}{3} = \frac{68}{3} \approx 22.67 < 2...
Try \( v = 6 \):

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