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Home » \frac1{R_{\texttotal}} = \frac112 + \frac16 + \frac14 - Dyverse

\frac1{R_{\texttotal}} = \frac112 + \frac16 + \frac14 - Dyverse

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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底面の半径が4cm、高さが9cmの円錐があります。その体積を計算してください...
V = \frac{1}{3} \pi r^2 h = \frac{1}{3} \pi \times 4^2 \times 9 = \fra...
#### 48\pi
方程式 \( 2x^2 - 8x + 6 = 0 \) を \( x \) について解いてください。
二次方程式の公式 \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) を使用し...
x = \frac{-(-8) \pm \sqrt{(-8)^2 - 4 \times 2 \times 6}}{2 \times 2}
x = \frac{8 \
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