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Home » h = \sqrt{10^2 - \left(\fracb2\right)^2} = \sqrt{100 - \fracb^24} - Dyverse

h = \sqrt{10^2 - \left(\fracb2\right)^2} = \sqrt{100 - \fracb^24} - Dyverse

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Substituting into the identity:
a^4 + b^4 = 1^2 - 2 \cdot \frac{1}{4} = 1 - \frac{1}{2} = \frac{1}{2}
|a^4 + b^4| = \left| \frac{1}{2} \right| = \boxed{\frac{1}{2}}
Solution: To minimize
under the constraint $ x + y + z = 1 $, we apply the **Cauchy-Schwarz...
Equality occurs when $ \frac{x}{y} = \frac{y}{z} = \frac{z}{x} $, whic...
\frac{(1/3)^2}{1/3} + \frac{(1/3)^2}{1/3} + \frac{(1/3)^2}{1/3} = 3 \c...
Therefore, the minimum value is $ \boxed{1} $.
Question: Compute the sum of the roots of the equation
u\sqrt{u} - 6u + 7\sqrt{u} - 12 = 0,

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