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Home » n^3 \equiv 13 \pmod125 - Dyverse

n^3 \equiv 13 \pmod125 - Dyverse

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 Multiply through by \( 6400 \) (LCM of 100 and 64):

📌 64x^2 + 100(64 - x^2) = 6400

📌 64x^2 + 6400 - 100x^2 = 6400

📌 -36x^2 = 0 \Rightarrow x^2 = 0

📌 Wait — this suggests only \( x = 0 \), but let's recheck:

📌 Correct substitution:

📌 \frac{x^2}{100} + 1 - \frac{x^2}{64} = 1

📌 x^2\left( \frac{1}{100} - \frac{1}{64} \right) = 0

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