Setting \( g'(t) = 0 \) gives the equation \( 3t^2 - 8t + 4 = 0 \). Solving this quadratic equation using the quadratic formula \( t = rac{-b \pm \sqrtb^2 - 4ac}2a \), where \( a = 3 \), \( b = -8 \), and \( c = 4 \), we find: - Dyverse