Solution: A regular hexagon can be divided into 6 equilateral triangles, each with side length 3 cm. The area of one equilateral triangle is $\frac{\sqrt3}4 \times 3^2 = \frac{9\sqrt3}4$. The total area is $6 \times \frac{9\sqrt3}4 = \frac{54\sqrt3}4 = \frac{27\sqrt3}2$. - Dyverse