t = \frac{\ln\left(\frac32\right)}{\ln\left(\frac1.051.03\right)} \approx \frac0.40550.0198 \approx 20.48

t = \frac{\ln\left(\frac32\right)}{\ln\left(\frac1.051.03\right)} \approx \frac0.40550.0198 \approx 20.48 - Dyverse

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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