The area of the triangle is given by \( \frac12ab \). The semi-perimeter \( s \) of the triangle is \( \fraca + b + c2 \). The radius of the inscribed circle \( r \) can be expressed as \( r = \fracAs \), where \( A \) is the area of the triangle. Therefore, \( r = \frac{\frac12ab}{\fraca + b + c2} = \fracaba + b + c \). The area of the inscribed circle is \( \pi r^2 \). Substituting for \( r \), the area of the circle is \( \pi \left(\fracaba + b + c\right)^2 \). The ratio of the area of the circle to the area of the triangle is: - Dyverse