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Home » Then, calculate \( H \): - Dyverse

Then, calculate \( H \): - Dyverse

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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x^4 + 8x^2 + 16 - 16y^4 + 64 = x^4 + 8x^2 + 80 - 16y^4
Now factor $ x^4 + 8x^2 + 80 $:
Try factoring as $ (x^2 + a)^2 + b $, or test rational root theorem. L...
x^4 + 8x^2 + 80 = x^2(x^2 + 8) + 80
Not helpful. Try factoring as a quadratic in $ x^2 $:
Let $ u = x^2 $, then:
u^2 + 8u + 80 = (u + 4)^2 + 64
This is irreducible over real numbers. So the expression is:
This is the simplest factored form over the reals.
oxed{(x^2 + 4)^2 - 16(y^2 - 2)(y^2 + 2)}

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