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Home » x^4 + 8x^2 + 16 = (x^2 + 4)^2 - Dyverse

x^4 + 8x^2 + 16 = (x^2 + 4)^2 - Dyverse

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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We know \( a + b = 10 \) and \( a^2 + b^2 = 58 \). Use the identity:
a^2 + b^2 = (a+b)^2 - 2ab
= 10^2 - 2ab \implies 58 = 100 - 2ab \implies 2ab = 42 \implies ab = 2...
Now substitute \( a+b \), \( a^2+b^2 \), and \( ab \) into the sum of...
Question:** A cartographer is designing a map transformation function...
First, find \( g(3) \):
g(3) = 2(3) + 1 = 7
Now substitute \( x = g(3) = 7 \) into \( T(x) \):
T(7) = 3(7)^2 - 2(7) + 5
3(7)^2 = 3 \times 49 = 147

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$24 = 2^3 \cdot 3$,
$36 = 2^2 \cdot 3^2$.
The LCM is found by taking the highest powers of all primes:

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